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Topic 2/3
14 Flashcards in this deck.
A geometric progression (GP) is a sequence of numbers where each term after the first is found by multiplying the previous term by a fixed, non-zero number called the common ratio (\( r \)). The general form of a GP is:
$$ a, \ a \cdot r, \ a \cdot r^2, \ a \cdot r^3, \ldots $$Where:
For example, consider the GP: \( 2, 6, 18, 54, \ldots \). Here, the first term \( a = 2 \) and the common ratio \( r = 3 \).
The sum of the first \( n \) terms of a geometric progression is denoted by \( S_n \). The formula to calculate this sum depends on whether the common ratio \( r \) is equal to 1 or not.
These formulas allow for the efficient calculation of the sum without having to add each term individually.
To derive the formula for the sum of the first \( n \) terms of a GP where \( r \neq 1 \), consider the sum \( S_n \) as follows:
$$ S_n = a + a \cdot r + a \cdot r^2 + \ldots + a \cdot r^{n-1} $$Multiply both sides by \( r \):
$$ r \cdot S_n = a \cdot r + a \cdot r^2 + \ldots + a \cdot r^{n} $$Subtract the second equation from the first:
$$ S_n - r \cdot S_n = a - a \cdot r^{n} $$ $$ S_n (1 - r) = a (1 - r^{n}) $$ $$ S_n = a \cdot \frac{1 - r^n}{1 - r} $$This derivation confirms the validity of the sum formula for geometric progressions.
Let's consider an example to illustrate how to apply the sum formula.
Here, \( a = 3 \) and \( r = 2 \).
Using the sum formula:
$$ S_5 = 3 \cdot \frac{1 - 2^5}{1 - 2} = 3 \cdot \frac{1 - 32}{-1} = 3 \cdot 31 = 93 $$Using the formula:
$$ S_4 = 5 \cdot \frac{1 - \left(\frac{1}{3}\right)^4}{1 - \frac{1}{3}} = 5 \cdot \frac{1 - \frac{1}{81}}{\frac{2}{3}} = 5 \cdot \frac{\frac{80}{81}}{\frac{2}{3}} = 5 \cdot \frac{80}{81} \cdot \frac{3}{2} = 5 \cdot \frac{240}{162} = 5 \cdot \frac{80}{54} = \frac{400}{54} \approx 7.41 $$While applying the sum formula, it's crucial to consider the value of the common ratio \( r \).
Understanding these scenarios helps in analyzing the behavior of geometric series in various contexts.
Geometric series have numerous applications in different fields:
These applications demonstrate the practical significance of mastering geometric progressions and their sums.
While the sum formula for a finite number of terms is essential, understanding infinite geometric series extends this knowledge to scenarios where the number of terms is unbounded.
An infinite geometric series is expressed as:
$$ S = a + a \cdot r + a \cdot r^2 + a \cdot r^3 + \ldots $$The sum of an infinite geometric series converges only if \( |r| < 1 \). Under this condition, the sum is given by:
$$ S = \frac{a}{1 - r} $$>This formula is pivotal in various mathematical models, such as calculating present values in perpetuities and analyzing signal behaviors in engineering.
Starting with the finite sum formula:
$$ S_n = a \cdot \frac{1 - r^n}{1 - r} $$>Taking the limit as \( n \) approaches infinity and considering \( |r| < 1 \):
$$ \lim_{n \to \infty} S_n = a \cdot \frac{1 - 0}{1 - r} = \frac{a}{1 - r} $$>This derivation shows how the finite sum formula transitions into the infinite case.
Beyond the closed-form sum, geometric progressions can also be analyzed using recursive relationships. A recursive formula defines each term based on the preceding term:
$$ a_{n} = a_{n-1} \cdot r, \quad \text{with} \quad a_1 = a $$>Understanding recursive formulas is essential in fields like computer science, where recursive algorithms often rely on such sequences.
Geometric progressions intersect with various disciplines, showcasing their versatility:
These connections highlight the importance of geometric series in practical and theoretical applications across different fields.
Advanced problems involving geometric series often require multi-step reasoning and the integration of multiple mathematical concepts. For instance:
Solution:
$$ S_{10} = 500 \cdot 3^{10} = 500 \cdot 59049 = 29,524,500 \ \text{bacteria} $$Solution:
$$ S = \frac{100}{0.05 - 0.02} = \frac{100}{0.03} = 3,333.\overline{3} $$These examples demonstrate the application of geometric series in complex scenarios, underscoring the necessity of a deep understanding of the underlying principles.
Aspect | Arithmetic Progression (AP) | Geometric Progression (GP) |
---|---|---|
Definition | A sequence where each term increases by a constant difference. | A sequence where each term increases by a constant ratio. |
Common Difference/Ratio | Constant difference (\( d \)). | Constant ratio (\( r \)). |
nth Term Formula | \( a_n = a + (n-1)d \) | \( a_n = a \cdot r^{n-1} \) |
Sum of n Terms | \( S_n = \frac{n}{2} [2a + (n-1)d] \) | \( S_n = a \cdot \frac{1 - r^n}{1 - r} \) (if \( r \neq 1 \)) |
Applications | Salary increments, simple interest calculations. | Compound interest, population growth models. |
Remember the acronym "ARITHMETIC vs GEOMETRIC" to differentiate progression types: A for Applying addition (Arithmetic) and G for Growth multiplicatively (Geometric). To quickly recall the sum formula for GPs, think "Multiply and Subtract": \( S_n = a \cdot \frac{1 - r^n}{1 - r} \). Practice deriving the formula to deepen your understanding and avoid memorization pitfalls. Also, always check if the common ratio \( r \) is 1 or not before applying the sum formula.
Did you know that geometric progressions are used to model phenomena such as radioactive decay and the depreciation of assets over time? In finance, the concept of compound interest relies heavily on geometric progressions to calculate the growth of investments. Additionally, the Fibonacci sequence, which appears in nature's patterns like the arrangement of leaves and the spirals of shells, can be related to geometric sequences when extended into more complex series.
Mistake 1: Forgetting to subtract 1 in the numerator of the sum formula.
Incorrect: \( S_n = a \cdot \frac{r^n}{1 - r} \)
Correct: \( S_n = a \cdot \frac{1 - r^n}{1 - r} \)
Mistake 2: Using the formula for arithmetic progressions instead of geometric progressions.
Incorrect Approach: Applying \( S_n = \frac{n}{2}(2a + (n - 1)d) \) to a GP.
Correct Approach: Use \( S_n = a \cdot \frac{1 - r^n}{1 - r} \).
Mistake 3: Misidentifying the common ratio (\( r \)) which leads to incorrect calculations of subsequent terms and sums.