All Topics
calculus-bc | collegeboard-ap
Responsive Image
4. Parametric Equations, Polar Coordinates and Vector-Valued Functions
Understanding the Integration by Parts Formula

Topic 2/3

left-arrow
left-arrow
archive-add download share

Understanding the Integration by Parts Formula

Introduction

Integration by parts is a fundamental technique in calculus, particularly within the AP Calculus BC curriculum of Collegeboard AP. This method transforms the integral of a product of functions into a more manageable form, facilitating the evaluation of complex integrals. Mastering integration by parts is essential for solving a wide range of problems involving polynomial, exponential, logarithmic, and trigonometric functions.

Key Concepts

1. The Integration by Parts Formula

Integration by parts is derived from the product rule for differentiation and provides a method to integrate products of functions. The formula is expressed as: $$ \int u \, dv = uv - \int v \, du $$ where: - \( u \) and \( dv \) are differentiable functions of \( x \), - \( du \) is the derivative of \( u \), - \( v \) is the integral of \( dv \). This formula allows us to choose parts of the integrand to simplify the integral.

2. Choosing \( u \) and \( dv \)

Selecting appropriate functions for \( u \) and \( dv \) is crucial for simplifying the integral. A common strategy is the LIATE rule, which prioritizes functions in the following order for \( u \): - **L**ogarithmic functions - **I**nverse trigonometric functions - **A**lgebraic functions - **T**rigonometric functions - **E**xponential functions By following this hierarchy, one can systematically choose \( u \) and \( dv \) to make the resulting integral easier to evaluate.

3. Step-by-Step Process

To apply integration by parts effectively, follow these steps:
  1. Identify and assign: Choose which part of the integrand will be \( u \) and which will be \( dv \) based on the LIATE rule.
  2. Differentiate and integrate: Differentiate \( u \) to find \( du \) and integrate \( dv \) to find \( v \).
  3. Apply the formula: Substitute \( u \), \( dv \), \( v \), and \( du \) into the integration by parts formula.
  4. Simplify and integrate: Evaluate the remaining integral \( \int v \, du \). If necessary, apply integration by parts again.

4. Examples

  1. Simple Polynomial and Exponential Function
  2. Consider the integral: $$ \int x e^{x} dx $$ Using LIATE, let \( u = x \) (Algebraic) and \( dv = e^{x} dx \) (Exponential). Then, $$ du = dx \\ v = e^{x} $$ Applying the formula: $$ \int x e^{x} dx = x e^{x} - \int e^{x} dx = x e^{x} - e^{x} + C = e^{x}(x - 1) + C $$
  3. Integration Involving Logarithmic Function
  4. Evaluate: $$ \int \ln(x) dx $$ Choose \( u = \ln(x) \) (Logarithmic) and \( dv = dx \) (Algebraic). Then, $$ du = \frac{1}{x} dx \\ v = x $$ Applying the formula: $$ \int \ln(x) dx = x \ln(x) - \int x \cdot \frac{1}{x} dx = x \ln(x) - \int 1 dx = x \ln(x) - x + C $$
  5. Trigonometric Function Example
  6. Compute: $$ \int x \sin(x) dx $$ Select \( u = x \) (Algebraic) and \( dv = \sin(x) dx \) (Trigonometric). Then, $$ du = dx \\ v = -\cos(x) $$ Applying the formula: $$ \int x \sin(x) dx = -x \cos(x) + \int \cos(x) dx = -x \cos(x) + \sin(x) + C $$

5. Tabular Integration by Parts

For integrals where repeated application of integration by parts is required, the tabular method streamlines the process. This is particularly useful when one part of the integrand reduces neatly to zero after a few differentiations.
  1. Create two columns: one for derivatives of \( u \) and one for integrals of \( dv \).
  2. Differentiate \( u \) repeatedly until it becomes zero.
  3. Integrate \( dv \) repeatedly the same number of times as \( u \) is differentiated.
  4. Multiply diagonally and alternate signs, then sum the results.
**Example:** Evaluate: $$ \int x^2 e^{x} dx $$
Derivatives of \( u \) Integrals of \( dv \)
\( x^2 \) \( e^{x} \)
\( 2x \) \( e^{x} \)
2 \( e^{x} \)
0
Applying the tabular method: $$ \int x^2 e^{x} dx = x^2 e^{x} - 2x e^{x} + 2 e^{x} + C = e^{x}(x^2 - 2x + 2) + C $$

6. Integration by Parts for Definite Integrals

The integration by parts technique also applies to definite integrals, with limits of integration applied to the \( uv \) term. **Formula:** $$ \int_{a}^{b} u \, dv = \left[ uv \right]_{a}^{b} - \int_{a}^{b} v \, du $$ **Example:** Evaluate: $$ \int_{0}^{\pi} x \sin(x) dx $$ Choose \( u = x \) and \( dv = \sin(x) dx \), then \( du = dx \) and \( v = -\cos(x) \). Applying the formula: $$ \int_{0}^{\pi} x \sin(x) dx = \left[ -x \cos(x) \right]_{0}^{\pi} + \int_{0}^{\pi} \cos(x) dx $$ $$ = -\pi \cos(\pi) + 0 \cdot \cos(0) + \left[ \sin(x) \right]_{0}^{\pi} $$ $$ = -\pi(-1) + (0 - 0) = \pi $$

7. Reduction Formulas

Reduction formulas are recursive relations that reduce the power of a function in an integral, simplifying the evaluation of more complex integrals. **Example:** Find: $$ \int \sin^n(x) dx $$ Using integration by parts: Let \( u = \sin^{n-1}(x) \) and \( dv = \sin(x) dx \). Then \( du = (n-1)\sin^{n-2}(x) \cos(x) dx \) and \( v = -\cos(x) \). Applying the formula: $$ \int \sin^n(x) dx = -\sin^{n-1}(x) \cos(x) + (n-1) \int \sin^{n-2}(x) \cos^2(x) dx $$ Using the identity \( \cos^2(x) = 1 - \sin^2(x) \): $$ = -\sin^{n-1}(x) \cos(x) + (n-1) \int \sin^{n-2}(x) (1 - \sin^2(x)) dx $$ $$ = -\sin^{n-1}(x) \cos(x) + (n-1) \int \sin^{n-2}(x) dx - (n-1) \int \sin^n(x) dx $$ Rearranging: $$ \int \sin^n(x) dx = -\frac{\sin^{n-1}(x) \cos(x)}{n} + \frac{n-1}{n} \int \sin^{n-2}(x) dx $$ This reduction formula allows the evaluation of \( \int \sin^n(x) dx \) by expressing it in terms of \( \int \sin^{n-2}(x) dx \), simplifying the integral step by step.

8. Applications of Integration by Parts

  • Solving Differential Equations: Integration by parts is instrumental in solving certain types of differential equations, especially linear ones where the method of undetermined coefficients is used.
  • Physics Applications: In physics, this technique is employed in deriving formulas related to work, energy, and various integrals in electromagnetism and quantum mechanics.
  • Probability and Statistics: It is used in finding expected values and moments of probability distributions.
  • Engineering: Integration by parts is applied in signal processing, control systems, and other engineering fields where integrals of products of functions frequently arise.

9. Common Challenges and Tips

  • Choosing \( u \) and \( dv \): Incorrect selection can lead to more complicated integrals. Following the LIATE rule helps in making an appropriate choice.
  • Reapplication of the Formula: Some integrals require multiple applications of integration by parts. Recognizing when to apply the method again is essential.
  • Identifying Patterns: In cases where integration by parts leads to an equation involving the original integral, solving for the integral algebraically can simplify the process.
  • Tabular Method: Utilizing the tabular integration method can save time and reduce the complexity of calculations for repetitive integrations.
  • Practice: Regular practice with a variety of integrals enhances proficiency and intuition for selecting the best approach.

10. Advanced Topics

  • Integration by Parts in Multiple Dimensions: Extending the method to functions of several variables using techniques like integration by parts for partial derivatives.
  • Asymptotic Analysis: Applying integration by parts in the context of asymptotic expansions to approximate integrals.
  • Integration in the Complex Plane: Using the method for complex integrals involving holomorphic and meromorphic functions.

Comparison Table

Aspect Integration by Parts Substitution Method
Primary Use Integrating products of functions. Simplifying integrals by changing variables.
Typical Functions Polynomial, exponential, logarithmic, trigonometric functions. Composite functions where one function is a derivative of another.
Complexity Can require multiple applications or tabular methods. Generally straightforward when applicable.
Resulting Integral Transforms into another integral, which may be simpler. Eliminates the original variable in favor of a new one.
Examples \(\int x e^{x} dx\), \(\int \ln(x) dx\) \(\int 2x dx\) using substitution \( u = x^2 \)

Summary and Key Takeaways

  • Integration by parts is essential for integrating products of functions in Calculus BC.
  • Choosing \( u \) and \( dv \) wisely, often guided by the LIATE rule, simplifies the process.
  • The technique can be applied multiple times and is compatible with methods like tabular integration.
  • Mastering integration by parts opens doors to solving complex integrals across various scientific disciplines.

Coming Soon!

coming soon
Examiner Tip
star

Tips

Use the LIATE Rule: Remember the order: Logarithmic, Inverse trigonometric, Algebraic, Trigonometric, Exponential. This hierarchy helps in selecting \( u \) effectively.

Practice with Diverse Examples: Engage with a variety of integrals to build intuition on when and how to apply integration by parts.

Check Your Work: After integrating, differentiate your result to ensure it matches the original integrand.

Memorize Common Formulas: Familiarity with standard integrals can speed up the process and reduce errors during exams.

Did You Know
star

Did You Know

Integration by parts has its roots in the ancient method of integration used by mathematicians like Isaac Newton and Gottfried Wilhelm Leibniz. Interestingly, this technique is not only pivotal in pure mathematics but also plays a crucial role in fields like quantum mechanics, where it helps in evaluating expectation values of certain operators. Additionally, integration by parts is instrumental in deriving the famous Fourier series, which is fundamental in signal processing and acoustics.

Common Mistakes
star

Common Mistakes

1. Incorrect Selection of \( u \) and \( dv \): Students often choose \( dv \) as a more complex part, leading to harder integrals. Incorrect: Letting \( dv = x\,dx \) and \( u = e^x \) in \( \int x e^x dx \). Correct: Letting \( u = x \) and \( dv = e^x dx \).

2. Forgetting the \( du \) or \( v \) Components: After differentiation and integration, forgetting to correctly substitute \( du \) and \( v \) into the formula. Always ensure both are accounted for to avoid incomplete solutions.

3. Neglecting the Constant of Integration in Indefinite Integrals: Omitting the "+ C" can lead to incorrect final answers. Always include the constant when dealing with indefinite integrals.

FAQ

When should I use integration by parts instead of substitution?
Use integration by parts when dealing with the product of two functions where one can be easily differentiated and the other easily integrated, especially when substitution doesn't simplify the integral.
Can integration by parts be used multiple times on the same integral?
Yes, some integrals require repeated applications of integration by parts to fully simplify and solve them.
What is the LIATE rule and why is it important?
The LIATE rule is a guideline for choosing which part of the integrand to set as \( u \) and \( dv \). It stands for Logarithmic, Inverse trigonometric, Algebraic, Trigonometric, and Exponential functions, prioritizing \( u \) selection to simplify the integral.
What is the tabular method in integration by parts?
The tabular method is a streamlined approach for applying integration by parts multiple times, especially useful when one function reduces to zero after several differentiations.
How do I handle definite integrals with integration by parts?
When dealing with definite integrals, apply the integration by parts formula and evaluate the \( uv \) term at the limits of integration, then subtract the integral of \( v \, du \) over the same limits.
Is integration by parts applicable to improper integrals?
Yes, integration by parts can be utilized for improper integrals, but ensure convergence criteria are met when applying limits to the integration.
4. Parametric Equations, Polar Coordinates and Vector-Valued Functions
Download PDF
Get PDF
Download PDF
PDF
Share
Share
Explore
Explore